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If (kx+4y=38) and (x-y=3) have solution (x=7,\ y=4), what will be the value of (k)?

Answer and explanation

Correct answer: \(k=\frac{22}{7}\)

Substitute the given solution \(x=7\) and \(y=4\) into \(kx+4y=38\): \(7k+4(4)=38\). Thus, \(7k+16=38\), so \(7k=22\) and \(k=\frac{22}{7}\). Hence, option B is correct. The equation \(x-y=3\) only verifies the given solution, since \(7-4=3\). Exam tip: To find a parameter, substitute the given solution into the equation containing that parameter.

Related tags

Pair Of Linear EquationsSubstitution MethodParameterValue Of KClass 10 MathematicsAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two Variables

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