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What is the value of (x+y) from (0.4x+0.7y=5.3) and (0.8x-0.2y=3.8)?

Answer and explanation

Correct answer: \(x+y=\frac{161}{16}\)

Multiply both equations by 10 to remove decimals: \(4x+7y=53\) and \(8x-2y=38\). Dividing the second equation by 2 gives \(4x-y=19\), so \(y=4x-19\). Substituting this into the first equation, \(4x+7(4x-19)=53\), gives \(x=\frac{93}{16}\) and \(y=\frac{17}{4}\). Therefore, \(x+y=\frac{161}{16}\). Note that \(\frac{93}{16}\) is the value of \(x\) alone, not of the sum. Exam tip: remove decimals first when solving linear equations with decimal coefficients.

Related tags

Pair Of Linear EquationsSubstitution MethodElimination MethodDecimal CoefficientsAlgebraClass 10Algebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination Method

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