If (2(x+y)+3(x-y)=41) and (3(x+y)-2(x-y)=34), what is the value of (y)?यदि (2(x+y)+3(x-y)=41) और (3(x+y)-2(x-y)=34), तो (y) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (y=\frac{25}{13})(y=\frac{25}{13})
Let (x+y=s) and (x-y=d). Solving gives (s=\frac{184}{13}) and (d=\frac{134}{13}), so (y=\frac{25}{13}).(x+y=s) और (x-y=d) मानकर हल करें। (s=\frac{184}{13}) और (d=\frac{134}{13}), इसलिए (y=\frac{25}{13})।
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