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The sum of the present ages of a father and son is (56) years. (4) years ago, the father's age was (5) times the son's age. What is the son's present age?

Answer and explanation

Correct answer: (12) years

The direct answer is option B: the son is 12 years old now. Let the father’s present age be f and the son’s be s. Their present sum gives f+s=56. Four years ago, their ages were f-4 and s-4, and the father was five times the son: f-4=5(s-4). Expand: f-4=5s-20, so f=5s-16. Substitute into f+s=56: 5s-16+s=56, hence 6s=72 and s=12. Then f=44. Four years ago they were 40 and 8, and 40=5×8, so the result checks. Option A, 10, would make the father 46 and past ages 42 and 6, not five times. Option C, 14, gives father 42 and past ages 38 and 10. Option D, 16, gives father 40 and past ages 36 and 12. Always subtract four from both ages, not just one.

Related tags

Linear EquationsAge ProblemSubstitutionClass 10

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