What is the value of (x+y) from (0.2x+0.5y=3.1) and (0.4x-0.1y=1.3)?समीकरणों (0.2x+0.5y=3.1) और (0.4x-0.1y=1.3) से (x+y) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x+y=\frac{97}{11})(x+y=\frac{97}{11})
Removing decimals gives (2x+5y=31) and (4x-y=13). The solution is (x=\frac{48}{11},\ y=\frac{49}{11}), so (x+y=\frac{97}{11}).दशमलव हटाने पर (2x+5y=31) और (4x-y=13) मिलते हैं। हल (x=\frac{48}{11},\ y=\frac{49}{11}), इसलिए (x+y=\frac{97}{11})।
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