If (3(x+y)+2(x-y)=31) and (2(x+y)-(x-y)=13), what is the value of (x)?यदि (3(x+y)+2(x-y)=31) और (2(x+y)-(x-y)=13), तो (x) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (x=\frac{40}{7})(x=\frac{40}{7})
Let (x+y=s) and (x-y=d). Solving gives (s=\frac{57}{7}) and (d=\frac{23}{7}), so (x=\frac{40}{7}).(x+y=s) और (x-y=d) मानें। हल करने पर (s=\frac{57}{7}) और (d=\frac{23}{7}), इसलिए (x=\frac{40}{7})।
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