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The sum of the ages of a father and son is (50) years. After (5) years, the father’s age will be (2) times the son’s age. What is the father’s present age?

Answer and explanation

Correct answer: 35 years

Let the present ages of the father and son be \(x\) years and \(y\) years respectively. Then \(x+y=50\). The condition after 5 years gives \(x+5=2(y+5)\), which simplifies to \(x-2y=5\). Solving this with \(x+y=50\) gives \(y=15\) and \(x=35\). Therefore, the father's present age is 35 years. If the father were 40 years old, the son would be 10; after 5 years, 45 would not be twice 15. Exam tip: in age problems, add the stated number of years to both ages for a future condition.

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Pair Of Linear EquationsAge ProblemsElimination MethodSubstitution MethodClass 10 MathematicsAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two V

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