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If (kx+3y=25) and (x-y=2) have solution (x=5,\ y=3), what is the value of (k)?

Answer and explanation

Correct answer: \(k=\frac{16}{5}\)

The given solution \(x=5, y=3\) must satisfy \(kx+3y=25\). Thus, \(5k+3(3)=25\), so \(5k+9=25\). Hence \(5k=16\) and \(k=\frac{16}{5}\). For instance, using \(k=\frac{14}{5}\) makes the left-hand side \(23\), not \(25\). Exam tip: when a solution is given, substitute its values directly into the original equation.

Related tags

Linear EquationsSubstitution MethodParameterAlgebraClass 10Algebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two Variables

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