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If (4x+5y=31) and (2x+y=11), what is the solution for (x) and (y)?

Answer and explanation

Correct answer: \(x=4,\ y=3\)

From the second equation, \(y=11-2x\). Substituting this into \(4x+5y=31\) gives \(4x+5(11-2x)=31\), so \(-6x=-24\). Hence, \(x=4\) and \(y=3\). The close distractor \(x=5,\ y=1\) satisfies the second equation, but it gives \(4(5)+5(1)=25\), not 31, in the first equation. Exam tip: always verify the ordered pair in both original equations.

Related tags

Pair Of Linear EquationsSubstitution MethodAlgebraic MethodsClass 10MathematicsAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two Variables

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