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On a road the first gap between two poles is 18 metres and each next gap increases by 9 metres. What is the total distance of the first 17 gaps?

Answer and explanation

Correct answer: 1530

The successive gaps are 18, 27, 36, and so on, so they form an arithmetic progression. The first term is a = 18, the common difference is d = 9, and the number of gaps is n = 17. Because the question asks for total distance, not just the last gap, use S_n = n/2[2a + (n − 1)d]. Thus S_17 = 17/2[2(18) + 16(9)] = 17/2[36 + 144] = 17/2 × 180 = 17 × 90 = 1530 metres. Therefore, option A is correct. The 17th gap alone would be 18 + 16×9 = 162 metres, so confusing a_n with S_n could lead to an incorrect distractor. The other values also do not satisfy the required sum.

Related tags

MathematicsArithmetic ProgressionSum Of TermsDistanceWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions ApClass 10 Mcq

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