यदि (p(x)=x-2+\(\sqrt{5}-2\)x-2\sqrt{5}), तो कौन सा युग्म शून्यक हो सकता है?
If (p(x)=x-2+\(\sqrt{5}-2\)x-2\sqrt{5}), which pair can be its zeroes?
Explanation opens after your attempt
Correct Answer
A. (2) और \(-\sqrt{5}\)(2) and \(-\sqrt{5}\)
Concept
The sum is \(2-\sqrt{5}\), so the coefficient of (x) is (-\(2-\sqrt{5}\)=\sqrt{5}-2). The product \(-2\sqrt{5}\) also matches.
Why this answer is correct
The correct answer is A. (2) और \(-\sqrt{5}\) / (2) and \(-\sqrt{5}\). The sum is \(2-\sqrt{5}\), so the coefficient of (x) is (-\(2-\sqrt{5}\)=\sqrt{5}-2). The product \(-2\sqrt{5}\) also matches.
Exam Tip
योग \(2-\sqrt{5}\) है, इसलिए (x) का गुणांक (-\(2-\sqrt{5}\)=\sqrt{5}-2) है। गुणनफल \(-2\sqrt{5}\) भी सही है।
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