Concept-wise Practice

zeroes-expression MCQ Questions for Class 10

zeroes-expression se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with zeroes-expression.

यदि \(\alpha=4+\sqrt{15}\) और \(\beta=4-\sqrt{15}\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha=4+\sqrt{15}\) and \(\beta=4-\sqrt{15}\), what is the value of \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. (62)

Step 1

Concept

Here \(\alpha+\beta=8\) and \(\alpha\beta=1\), so \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{64-2}{1}=62\). In such questions, first find the sum and product.

Step 2

Why this answer is correct

The correct answer is A. (62). Here \(\alpha+\beta=8\) and \(\alpha\beta=1\), so \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{64-2}{1}=62\). In such questions, first find the sum and product.

Step 3

Exam Tip

\(\alpha+\beta=8\) और \(\alpha\beta=1\), इसलिए \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{64-2}{1}=62\)। ऐसे प्रश्नों में पहले योग और गुणनफल निकालें।

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यदि \(\alpha\) और \(\beta\) \(x^2-3x-2\) के शून्यक हैं, तो (\(\alpha-\beta\)2) क्या है?

If \(\alpha\) and \(\beta\) are zeroes of \(x^2-3x-2\), what is (\(\alpha-\beta\)2)?

Explanation opens after your attempt
Correct Answer

A. (17)

Step 1

Concept

(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=32-4(-2)=17). This method gives the answer without finding the zeroes.

Step 2

Why this answer is correct

The correct answer is A. (17). (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=32-4(-2)=17). This method gives the answer without finding the zeroes.

Step 3

Exam Tip

(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=32-4(-2)=17)। यह तरीका शून्यक निकाले बिना उत्तर देता है।

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