एक वर्गाकार टाइल की भुजा (x) सेमी है। यदि (5) सेमी चौड़ा बॉर्डर लगाने पर कुल क्षेत्रफल (900) वर्ग सेमी हो जाता है तो मूल भुजा क्या है?
A square tile has side (x) cm. If a (5) cm wide border is added all around and the total area becomes (900) square cm, what is the original side?
Explanation opens after your attempt
Correct Answer
C. (20) सेमी/(20) cm
Step 1
Concept
After the border, the side becomes (x+10). From ((x+10)2=900), (x+10=30), so (x=20).
Step 2
Why this answer is correct
The correct answer is C. (20) सेमी / (20) cm. After the border, the side becomes (x+10). From ((x+10)2=900), (x+10=30), so (x=20).
Step 3
Exam Tip
बॉर्डर के बाद भुजा (x+10) होगी। ((x+10)2=900) से (x+10=30) और (x=20) मिलता है।
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एक वर्ग का क्षेत्रफल \(225 cm^2\) है। यदि उसकी भुजा (x cm) बढ़ाकर नया क्षेत्रफल (400 cm\(^2) कर दिया जाए, तो (x) क्या है\)?
The area of a square is (225 cm\(^2). If its side is increased by (x\) cm) and the new area becomes (400 cm\(^2), what is (x)\)?
Explanation opens after your attempt
Step 1
Concept
The original side is \(\sqrt{225}=15\), and the new side is \(\sqrt{400}=20\). Hence (x=20-15=5).
Step 2
Why this answer is correct
The correct answer is C. (5 cm\(). The original side is (\sqrt{225}=15), and the new side is (\sqrt{400}=20). Hence (x=20-15=5).\)
Step 3
Exam Tip
मूल भुजा \(\sqrt{225}=15\) है और नई भुजा \(\sqrt{400}=20\) है। अतः (x=20-15=5)।
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एक वर्गाकार पार्क का क्षेत्रफल (196) है। उसकी भुजा में (4) बढ़ाने पर नया क्षेत्रफल कितना होगा?
A square park has area (196). If its side is increased by (4), what will be the new area?
Explanation opens after your attempt
Step 1
Concept
If the original side is (x), then \(x^2=196\), so (x=14). The new side is (18), and the new area is \(18^2=324\).
Step 2
Why this answer is correct
The correct answer is A. (324). If the original side is (x), then \(x^2=196\), so (x=14). The new side is (18), and the new area is \(18^2=324\).
Step 3
Exam Tip
मूल भुजा (x) हो तो \(x^2=196\), इसलिए (x=14)। नई भुजा (18) है और नया क्षेत्रफल \(18^2=324\)।
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एक वर्गाकार पार्क का क्षेत्रफल (144) है। उसकी भुजा में (3) बढ़ाने पर नया क्षेत्रफल कितना होगा?
A square park has area (144). If its side is increased by (3), what will be the new area?
Explanation opens after your attempt
Step 1
Concept
If the original side is (x), then \(x^2=144\), so (x=12). The new side is (15), and the new area is \(15^2=225\).
Step 2
Why this answer is correct
The correct answer is A. (225). If the original side is (x), then \(x^2=144\), so (x=12). The new side is (15), and the new area is \(15^2=225\).
Step 3
Exam Tip
मूल भुजा (x) हो तो \(x^2=144\), इसलिए (x=12)। नई भुजा (15) है और नया क्षेत्रफल \(15^2=225\)।
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एक वर्ग का क्षेत्रफल उसकी भुजा के (10) गुने से (21) अधिक है। यदि भुजा (x) है, तो समीकरण कौन-सा है?
The area of a square is (21) more than (10) times its side. If the side is (x), which equation is correct?
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x-21=0\)
Step 1
Concept
The area is \(x^2\), and it is given that \(x^2=10x+21\). Therefore \(x^2-10x-21=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x-21=0\). The area is \(x^2\), and it is given that \(x^2=10x+21\). Therefore \(x^2-10x-21=0\) is correct.
Step 3
Exam Tip
क्षेत्रफल \(x^2\) है और दिया है \(x^2=10x+21\)। इसलिए \(x^2-10x-21=0\) सही है।
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एक वर्ग का क्षेत्रफल उसकी भुजा के (8) गुने से (15) अधिक है। यदि भुजा (x) है, तो समीकरण कौन-सा है?
The area of a square is (15) more than (8) times its side. If the side is (x), which equation is correct?
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x-15=0\)
Step 1
Concept
The area is \(x^2\), and it is given that \(x^2=8x+15\). Therefore \(x^2-8x-15=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x-15=0\). The area is \(x^2\), and it is given that \(x^2=8x+15\). Therefore \(x^2-8x-15=0\) is correct.
Step 3
Exam Tip
क्षेत्रफल \(x^2\) है और दिया है \(x^2=8x+15\)। इसलिए \(x^2-8x-15=0\) सही है।
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एक वर्ग का क्षेत्रफल उसकी भुजा के (6) गुने से (7) अधिक है। यदि भुजा (x) है, तो समीकरण कौन-सा है?
The area of a square is (7) more than (6) times its side. If the side is (x), which equation is correct?
Explanation opens after your attempt
Correct Answer
A. \(x^2-6x-7=0\)
Step 1
Concept
The area is \(x^2\) and it is given that \(x^2=6x+7\). Therefore \(x^2-6x-7=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-6x-7=0\). The area is \(x^2\) and it is given that \(x^2=6x+7\). Therefore \(x^2-6x-7=0\) is correct.
Step 3
Exam Tip
क्षेत्रफल \(x^2\) है और दिया है \(x^2=6x+7\)। इसलिए \(x^2-6x-7=0\) सही है।
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