Question 1/3
Medium Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30
एक वर्ग का क्षेत्रफल उसकी भुजा के (10) गुने से (21) अधिक है। यदि भुजा (x) है, तो समीकरण कौन-सा है?
The area of a square is (21) more than (10) times its side. If the side is (x), which equation is correct?
Explanation opens after your attempt
Correct Answer
A. \(x^2-10x-21=0\)
Step 1
Concept
The area is \(x^2\), and it is given that \(x^2=10x+21\). Therefore \(x^2-10x-21=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x-21=0\). The area is \(x^2\), and it is given that \(x^2=10x+21\). Therefore \(x^2-10x-21=0\) is correct.
Step 3
Exam Tip
क्षेत्रफल \(x^2\) है और दिया है \(x^2=10x+21\)। इसलिए \(x^2-10x-21=0\) सही है।
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Question 2/3
Medium Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
एक वर्ग का क्षेत्रफल उसकी भुजा के (8) गुने से (15) अधिक है। यदि भुजा (x) है, तो समीकरण कौन-सा है?
The area of a square is (15) more than (8) times its side. If the side is (x), which equation is correct?
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x-15=0\)
Step 1
Concept
The area is \(x^2\), and it is given that \(x^2=8x+15\). Therefore \(x^2-8x-15=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x-15=0\). The area is \(x^2\), and it is given that \(x^2=8x+15\). Therefore \(x^2-8x-15=0\) is correct.
Step 3
Exam Tip
क्षेत्रफल \(x^2\) है और दिया है \(x^2=8x+15\)। इसलिए \(x^2-8x-15=0\) सही है।
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Question 3/3
Medium Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28
एक वर्ग का क्षेत्रफल उसकी भुजा के (6) गुने से (7) अधिक है। यदि भुजा (x) है, तो समीकरण कौन-सा है?
The area of a square is (7) more than (6) times its side. If the side is (x), which equation is correct?
Explanation opens after your attempt
Correct Answer
A. \(x^2-6x-7=0\)
Step 1
Concept
The area is \(x^2\) and it is given that \(x^2=6x+7\). Therefore \(x^2-6x-7=0\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-6x-7=0\). The area is \(x^2\) and it is given that \(x^2=6x+7\). Therefore \(x^2-6x-7=0\) is correct.
Step 3
Exam Tip
क्षेत्रफल \(x^2\) है और दिया है \(x^2=6x+7\)। इसलिए \(x^2-6x-7=0\) सही है।
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