(18) identical balls को (6) boxes में रखना है और exactly (3) boxes non-empty हों, तो count कौन-सी है?
Explanation opens after your attempt
Correct Answer
A. \(^{6}C_3{}^{17}C_2\)
Concept
First choose the (3) non-empty boxes and then split (18) balls into (3) positive parts. In exams use choose boxes plus positive stars and bars for exactly non-empty.
Why this answer is correct
The correct answer is A. \(^{6}C_3{}^{17}C_2\). First choose the (3) non-empty boxes and then split (18) balls into (3) positive parts. In exams use choose boxes plus positive stars and bars for exactly non-empty.
Exam Tip
पहले (3) non-empty boxes चुनें फिर (18) balls को (3) positive parts में बांटें। परीक्षा में exactly non-empty को choose boxes plus positive stars-bars करें।
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