यदि रेखा (y=x+2) (x)-अक्ष को काटती है तो कटान का (x)-मान क्या है?
If the line (y=x+2) cuts the (x)-axis then what is the (x)-value of the intersection?
Explanation opens after your attempt
A. (-2)
Concept
Put (y=0) on the (x)-axis to get (x+2=0). Tip: setting (y=0) is the easiest method.
Why this answer is correct
The correct answer is A. (-2). Put (y=0) on the (x)-axis to get (x+2=0). Tip: setting (y=0) is the easiest method.
Exam Tip
(x)-अक्ष पर (y=0) रखकर (x+2=0) मिलता है। टिप: (y=0) रखना सबसे आसान तरीका है।
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