Question 1/2
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि समीकरण (x-2 -2(m+2)x+(m+2)2 =0) के मूल बराबर हैं तो (m) के लिए क्या सही है?
If roots of (x-2 -2(m+2)x+(m+2)2 =0) are equal, what is true for (m)?
#roots
#equal_roots
#identity_parameter
A हर वास्तविक (m) / Every real (m)
B केवल (m=0) / Only (m=0)
C केवल (m=-2) / Only (m=-2)
D कोई वास्तविक (m) नहीं / No real (m)
Explanation opens after your attempt
Correct Answer
A. हर वास्तविक (m) / Every real (m)
Step 1
Concept
The equation becomes ((x-(m+2))2 =0). Therefore the roots are equal for every real (m).
Step 2
Why this answer is correct
The correct answer is A. हर वास्तविक (m) / Every real (m). The equation becomes ((x-(m+2))2 =0). Therefore the roots are equal for every real (m).
Step 3
Exam Tip
समीकरण ((x-(m+2))2 =0) बनता है। इसलिए हर वास्तविक (m) के लिए दोनों मूल बराबर होंगे।
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Question 2/2
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि (x-2 -2(m+1)x+\(m^2+2m+1\)=0) के मूल बराबर हैं तो (m) के लिए क्या सही है?
If roots of (x-2 -2(m+1)x+\(m^2+2m+1\)=0) are equal, what is true for (m)?
#roots
#equal_roots
#identity_parameter
A हर वास्तविक (m) / Every real (m)
B केवल (m=0) / Only (m=0)
C केवल (m=-1) / Only (m=-1)
D कोई वास्तविक (m) नहीं / No real (m)
Explanation opens after your attempt
Correct Answer
A. हर वास्तविक (m) / Every real (m)
Step 1
Concept
The constant term is ((m+1)2 ), and the equation becomes ((x-(m+1))2 =0). Hence roots are equal for every real (m).
Step 2
Why this answer is correct
The correct answer is A. हर वास्तविक (m) / Every real (m). The constant term is ((m+1)2 ), and the equation becomes ((x-(m+1))2 =0). Hence roots are equal for every real (m).
Step 3
Exam Tip
अचर पद ((m+1)2 ) है और समीकरण ((x-(m+1))2 =0) बनता है। इसलिए हर वास्तविक (m) के लिए मूल बराबर हैं।
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