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general_identity MCQ Questions for Class 10

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2 questions tagged with general_identity.

Question 1/2 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि \(x^2-Sx+P=0\) के मूल \(\alpha\) और \(\beta\) हैं तो (\(\alpha-\beta\)2) किसके बराबर है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-Sx+P=0\), what is (\(\alpha-\beta\)2) equal to?

Explanation opens after your attempt
Correct Answer

A. \(S^2-4P\)

Step 1

Concept

Here the sum of roots is (S) and product is (P). Therefore (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=S-2-4P).

Step 2

Why this answer is correct

The correct answer is A. \(S^2-4P\). Here the sum of roots is (S) and product is (P). Therefore (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=S-2-4P).

Step 3

Exam Tip

यहां मूलों का योग (S) और गुणनफल (P) है। इसलिए (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=S-2-4P) है।

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Question 2/2 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(x^2-Sx+P=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha^2+\beta^2\) किसके बराबर है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-Sx+P=0\), what is \(\alpha^2+\beta^2\) equal to?

Explanation opens after your attempt
Correct Answer

A. \(S^2-2P\)

Step 1

Concept

Here the sum of roots is (S) and product is (P). Therefore (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=S-2-2P).

Step 2

Why this answer is correct

The correct answer is A. \(S^2-2P\). Here the sum of roots is (S) and product is (P). Therefore (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=S-2-2P).

Step 3

Exam Tip

यहां मूलों का योग (S) और गुणनफल (P) है। इसलिए (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=S-2-2P) है।

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