यदि \(x^2-Sx+P=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\alpha^2+\beta^2\) किसके बराबर है?
If \(\alpha\) and \(\beta\) are roots of \(x^2-Sx+P=0\), what is \(\alpha^2+\beta^2\) equal to?
Explanation opens after your attempt
Correct Answer
A. \(S^2-2P\)
Concept
Here the sum of roots is (S) and product is (P). Therefore (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=S-2-2P).
Why this answer is correct
The correct answer is A. \(S^2-2P\). Here the sum of roots is (S) and product is (P). Therefore (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=S-2-2P).
Exam Tip
यहां मूलों का योग (S) और गुणनफल (P) है। इसलिए (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=S-2-2P) है।
Login to save your score, XP, coins and progress.