कौन सी रेखा (x=0) पर (y=-10) देती है और ढाल (8) रखती है?
Which line gives (y=-10) at (x=0) and has slope (8)?
#equation_selection
#positive_slope
#negative_intercept
A (y=8x-10)
B (y=-10x+8)
C (y=-8x-10)
D (y=8x+10)
Explanation opens after your attempt
Correct Answer
A. (y=8x-10)
Step 1
Concept
(y=-10) at (x=0) means (c=-10). With slope (8), the line is (y=8x-10).
Step 2
Why this answer is correct
The correct answer is A. (y=8x-10). (y=-10) at (x=0) means (c=-10). With slope (8), the line is (y=8x-10).
Step 3
Exam Tip
(x=0) पर (y=-10) का अर्थ (c=-10) है। ढाल (8) से रेखा (y=8x-10) है।
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कौन सी रेखा (x=0) पर (y=15) देती है और ढाल (-3) रखती है?
Which line gives (y=15) at (x=0) and has slope (-3)?
#equation_selection
#negative_slope
#intercept
A (y=3x+15)
B (y=-3x+15)
C (y=15x-3)
D (y=-15x+3)
Explanation opens after your attempt
Correct Answer
B. (y=-3x+15)
Step 1
Concept
At (x=0), (y=15) gives (c=15). With slope (-3), (y=-3x+15) is correct.
Step 2
Why this answer is correct
The correct answer is B. (y=-3x+15). At (x=0), (y=15) gives (c=15). With slope (-3), (y=-3x+15) is correct.
Step 3
Exam Tip
(x=0) पर (y=15) से (c=15) मिलता है। ढाल (-3) होने से (y=-3x+15) सही है।
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रेखा (y=6x+b) का (y)-अवरोध (13) है। समीकरण कौन सा होगा?
The line (y=6x+b) has (y)-intercept (13). Which equation is correct?
#parameter_intercept
#equation_selection
#linear_form
A (y=13x+6)
B (y=6x-13)
C (y=6x+13)
D (y=-6x+13)
Explanation opens after your attempt
Correct Answer
C. (y=6x+13)
Step 1
Concept
(b) is the (y)-intercept. Putting (b=13) gives (y=6x+13).
Step 2
Why this answer is correct
The correct answer is C. (y=6x+13). (b) is the (y)-intercept. Putting (b=13) gives (y=6x+13).
Step 3
Exam Tip
(b) (y)-अवरोध है। (b=13) रखने पर (y=6x+13) बनता है।
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रेखा (y=ax-5) की ढाल (-7) है। समीकरण कौन सा होगा?
The line (y=ax-5) has slope (-7). Which equation is correct?
#parameter_slope
#equation_selection
#negative_slope
A (y=7x-5)
B (y=-7x-5)
C (y=-5x-7)
D (y=5x-7)
Explanation opens after your attempt
Correct Answer
B. (y=-7x-5)
Step 1
Concept
The slope equals (a). Putting (a=-7) gives (y=-7x-5).
Step 2
Why this answer is correct
The correct answer is B. (y=-7x-5). The slope equals (a). Putting (a=-7) gives (y=-7x-5).
Step 3
Exam Tip
ढाल (a) के बराबर है। (a=-7) रखने पर (y=-7x-5) मिलता है।
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कौन सी रेखा मूल बिंदु से गुजरती है और ढाल (11) रखती है?
Which line passes through the origin and has slope (11)?
#origin
#slope
#equation_selection
A (y=11x)
B (y=x+11)
C (y=11x+1)
D (y=-11x)
Explanation opens after your attempt
Correct Answer
A. (y=11x)
Step 1
Concept
Passing through the origin means the (y)-intercept is (0). With slope (11), (y=11x) is correct.
Step 2
Why this answer is correct
The correct answer is A. (y=11x). Passing through the origin means the (y)-intercept is (0). With slope (11), (y=11x) is correct.
Step 3
Exam Tip
मूल बिंदु से गुजरने पर (y)-अवरोध (0) होता है। ढाल (11) होने से (y=11x) सही है।
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कौन सी रेखा ढाल (0) और (y)-अवरोध (-8) रखती है?
Which line has slope (0) and (y)-intercept (-8)?
#zero_slope
#negative_intercept
#equation_selection
A (y=-8x)
B (y=0x-8)
C (y=8x-8)
D (y=x-8)
Explanation opens after your attempt
Correct Answer
B. (y=0x-8)
Step 1
Concept
With slope (0), the coefficient of (x) is (0). With (y)-intercept (-8), the line is (y=0x-8).
Step 2
Why this answer is correct
The correct answer is B. (y=0x-8). With slope (0), the coefficient of (x) is (0). With (y)-intercept (-8), the line is (y=0x-8).
Step 3
Exam Tip
ढाल (0) होने पर (x) का गुणांक (0) होगा। (y)-अवरोध (-8) से (y=0x-8) है।
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यदि रेखा की ढाल (-6) है और (x=0) पर (y=5) है तो रेखा कौन सी है?
If a line has slope (-6) and (y=5) at (x=0), which line is it?
#equation_selection
#negative_slope
#intercept
A (y=6x+5)
B (y=-6x+5)
C (y=-5x+6)
D (y=-6x-5)
Explanation opens after your attempt
Correct Answer
B. (y=-6x+5)
Step 1
Concept
(y=5) at (x=0) means the (y)-intercept is (5). With slope (-6), the line is (y=-6x+5).
Step 2
Why this answer is correct
The correct answer is B. (y=-6x+5). (y=5) at (x=0) means the (y)-intercept is (5). With slope (-6), the line is (y=-6x+5).
Step 3
Exam Tip
(x=0) पर (y=5) का अर्थ (y)-अवरोध (5) है। ढाल (-6) से (y=-6x+5) बनता है।
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यदि रेखा की ढाल (-10) और (y)-अवरोध (8) है तो समीकरण कौन सा होगा?
If a line has slope (-10) and (y)-intercept (8), which equation is correct?
#negative_slope
#equation_selection
#intercept
A (y=10x+8)
B (y=8x-10)
C (y=-10x+8)
D (y=-8x+10)
Explanation opens after your attempt
Correct Answer
C. (y=-10x+8)
Step 1
Concept
The slope is the coefficient of (x) and the (y)-intercept is the constant term. So (y=-10x+8) is correct.
Step 2
Why this answer is correct
The correct answer is C. (y=-10x+8). The slope is the coefficient of (x) and the (y)-intercept is the constant term. So (y=-10x+8) is correct.
Step 3
Exam Tip
ढाल (x) का गुणांक और (y)-अवरोध स्थिर पद होता है। इसलिए (y=-10x+8) सही है।
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कौन सी रेखा (x=0) पर (y=-8) देती है और ढाल (6) रखती है?
Which line gives (y=-8) at (x=0) and has slope (6)?
#equation_selection
#positive_slope
#negative_intercept
A (y=6x-8)
B (y=-8x+6)
C (y=-6x-8)
D (y=6x+8)
Explanation opens after your attempt
Correct Answer
A. (y=6x-8)
Step 1
Concept
(y=-8) at (x=0) means (c=-8). With slope (6), the line is (y=6x-8).
Step 2
Why this answer is correct
The correct answer is A. (y=6x-8). (y=-8) at (x=0) means (c=-8). With slope (6), the line is (y=6x-8).
Step 3
Exam Tip
(x=0) पर (y=-8) का अर्थ (c=-8) है। ढाल (6) से रेखा (y=6x-8) है।
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कौन सी रेखा (x=0) पर (y=12) देती है और ढाल (-4) रखती है?
Which line gives (y=12) at (x=0) and has slope (-4)?
#equation_selection
#negative_slope
#intercept
A (y=4x+12)
B (y=-4x+12)
C (y=12x-4)
D (y=-12x+4)
Explanation opens after your attempt
Correct Answer
B. (y=-4x+12)
Step 1
Concept
At (x=0), (y=12) gives (c=12). With slope (-4), (y=-4x+12) is correct.
Step 2
Why this answer is correct
The correct answer is B. (y=-4x+12). At (x=0), (y=12) gives (c=12). With slope (-4), (y=-4x+12) is correct.
Step 3
Exam Tip
(x=0) पर (y=12) से (c=12) मिलता है। ढाल (-4) होने से (y=-4x+12) सही है।
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रेखा (y=4x+b) का (y)-अवरोध (11) है। समीकरण कौन सा होगा?
The line (y=4x+b) has (y)-intercept (11). Which equation is correct?
#parameter_intercept
#equation_selection
#linear_form
A (y=11x+4)
B (y=4x-11)
C (y=4x+11)
D (y=-4x+11)
Explanation opens after your attempt
Correct Answer
C. (y=4x+11)
Step 1
Concept
(b) is the (y)-intercept. Putting (b=11) gives (y=4x+11).
Step 2
Why this answer is correct
The correct answer is C. (y=4x+11). (b) is the (y)-intercept. Putting (b=11) gives (y=4x+11).
Step 3
Exam Tip
(b) (y)-अवरोध है। (b=11) रखने पर (y=4x+11) बनता है।
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रेखा (y=ax-3) की ढाल (-6) है। समीकरण कौन सा होगा?
The line (y=ax-3) has slope (-6). Which equation is correct?
#parameter_slope
#equation_selection
#negative_slope
A (y=6x-3)
B (y=-6x-3)
C (y=-3x-6)
D (y=3x-6)
Explanation opens after your attempt
Correct Answer
B. (y=-6x-3)
Step 1
Concept
The slope equals (a). Putting (a=-6) gives (y=-6x-3).
Step 2
Why this answer is correct
The correct answer is B. (y=-6x-3). The slope equals (a). Putting (a=-6) gives (y=-6x-3).
Step 3
Exam Tip
ढाल (a) के बराबर है। (a=-6) रखने पर (y=-6x-3) मिलता है।
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कौन सी रेखा मूल बिंदु से गुजरती है और ढाल (9) रखती है?
Which line passes through the origin and has slope (9)?
#origin
#slope
#equation_selection
A (y=9x)
B (y=x+9)
C (y=9x+1)
D (y=-9x)
Explanation opens after your attempt
Step 1
Concept
Passing through the origin means the (y)-intercept is (0). With slope (9), (y=9x) is correct.
Step 2
Why this answer is correct
The correct answer is A. (y=9x). Passing through the origin means the (y)-intercept is (0). With slope (9), (y=9x) is correct.
Step 3
Exam Tip
मूल बिंदु से गुजरने पर (y)-अवरोध (0) होता है। ढाल (9) होने से (y=9x) सही है।
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कौन सी रेखा ढाल (0) और (y)-अवरोध (-4) रखती है?
Which line has slope (0) and (y)-intercept (-4)?
#zero_slope
#negative_intercept
#equation_selection
A (y=-4x)
B (y=0x-4)
C (y=4x-4)
D (y=x-4)
Explanation opens after your attempt
Correct Answer
B. (y=0x-4)
Step 1
Concept
With slope (0), the coefficient of (x) is (0). With (y)-intercept (-4), the line is (y=0x-4).
Step 2
Why this answer is correct
The correct answer is B. (y=0x-4). With slope (0), the coefficient of (x) is (0). With (y)-intercept (-4), the line is (y=0x-4).
Step 3
Exam Tip
ढाल (0) होने पर (x) का गुणांक (0) होगा। (y)-अवरोध (-4) से (y=0x-4) है।
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यदि रेखा की ढाल (-5) है और (x=0) पर (y=3) है तो रेखा कौन सी है?
If a line has slope (-5) and (y=3) at (x=0), which line is it?
#equation_selection
#negative_slope
#intercept
A (y=5x+3)
B (y=-5x+3)
C (y=-3x+5)
D (y=-5x-3)
Explanation opens after your attempt
Correct Answer
B. (y=-5x+3)
Step 1
Concept
(y=3) at (x=0) means the (y)-intercept is (3). With slope (-5), the line is (y=-5x+3).
Step 2
Why this answer is correct
The correct answer is B. (y=-5x+3). (y=3) at (x=0) means the (y)-intercept is (3). With slope (-5), the line is (y=-5x+3).
Step 3
Exam Tip
(x=0) पर (y=3) का अर्थ (y)-अवरोध (3) है। ढाल (-5) से (y=-5x+3) बनता है।
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यदि रेखा की ढाल (-8) और (y)-अवरोध (5) है तो समीकरण कौन सा होगा?
If a line has slope (-8) and (y)-intercept (5), which equation is correct?
#negative_slope
#equation_selection
#intercept
A (y=8x+5)
B (y=5x-8)
C (y=-8x+5)
D (y=-5x+8)
Explanation opens after your attempt
Correct Answer
C. (y=-8x+5)
Step 1
Concept
The slope is the coefficient of (x) and the (y)-intercept is the constant term. So (y=-8x+5) is correct.
Step 2
Why this answer is correct
The correct answer is C. (y=-8x+5). The slope is the coefficient of (x) and the (y)-intercept is the constant term. So (y=-8x+5) is correct.
Step 3
Exam Tip
ढाल (x) का गुणांक और (y)-अवरोध स्थिर पद होता है। इसलिए (y=-8x+5) सही है।
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कौन सी रेखा (x=0) पर (y=-2) देती है और ढाल (-5) रखती है?
Which line gives (y=-2) at (x=0) and has slope (-5)?
#equation_selection
#negative_slope
#negative_intercept
A (y=5x-2)
B (y=-2x-5)
C (y=-5x-2)
D (y=-5x+2)
Explanation opens after your attempt
Correct Answer
C. (y=-5x-2)
Step 1
Concept
At (x=0), (y=-2) gives (c=-2). With slope (-5), (y=-5x-2) is correct.
Step 2
Why this answer is correct
The correct answer is C. (y=-5x-2). At (x=0), (y=-2) gives (c=-2). With slope (-5), (y=-5x-2) is correct.
Step 3
Exam Tip
(x=0) पर (y=-2) से (c=-2) मिलता है। ढाल (-5) होने से (y=-5x-2) सही है।
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कौन सी रेखा (x=0) पर (y=4) देती है और ढाल (3) रखती है?
Which line gives (y=4) at (x=0) and has slope (3)?
#equation_selection
#slope
#intercept
A (y=3x+4)
B (y=4x+3)
C (y=-3x+4)
D (y=3x-4)
Explanation opens after your attempt
Correct Answer
A. (y=3x+4)
Step 1
Concept
(y=4) at (x=0) means the (y)-intercept is (4). With slope (3), the line is (y=3x+4).
Step 2
Why this answer is correct
The correct answer is A. (y=3x+4). (y=4) at (x=0) means the (y)-intercept is (4). With slope (3), the line is (y=3x+4).
Step 3
Exam Tip
(x=0) पर (y=4) का अर्थ (y)-अवरोध (4) है। ढाल (3) से रेखा (y=3x+4) है।
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रेखा (y=-2x+b) का (y)-अवरोध (-6) है। समीकरण कौन सा होगा?
The line (y=-2x+b) has (y)-intercept (-6). Which equation is correct?
#parameter_intercept
#equation_selection
#negative_intercept
A (y=-2x+6)
B (y=-2x-6)
C (y=2x-6)
D (y=-6x-2)
Explanation opens after your attempt
Correct Answer
B. (y=-2x-6)
Step 1
Concept
(b) is the (y)-intercept. Putting (b=-6) gives (y=-2x-6).
Step 2
Why this answer is correct
The correct answer is B. (y=-2x-6). (b) is the (y)-intercept. Putting (b=-6) gives (y=-2x-6).
Step 3
Exam Tip
(b) ही (y)-अवरोध है। (b=-6) रखने पर (y=-2x-6) बनता है।
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रेखा (y=ax+4) की ढाल (9) है। समीकरण कौन सा होगा?
The line (y=ax+4) has slope (9). Which equation is correct?
#parameter_slope
#equation_selection
#linear_form
A (y=9x+4)
B (y=4x+9)
C (y=-9x+4)
D (y=9x-4)
Explanation opens after your attempt
Correct Answer
A. (y=9x+4)
Step 1
Concept
The slope equals (a). Putting (a=9) gives (y=9x+4).
Step 2
Why this answer is correct
The correct answer is A. (y=9x+4). The slope equals (a). Putting (a=9) gives (y=9x+4).
Step 3
Exam Tip
ढाल (a) के बराबर है। (a=9) रखने पर (y=9x+4) मिलता है।
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कौन सी रेखा ढाल (0) और (y)-अवरोध (9) रखती है?
Which line has slope (0) and (y)-intercept (9)?
#zero_slope
#y_intercept
#equation_selection
A (y=9x)
B (y=0x+9)
C (y=x+9)
D (y=-9x)
Explanation opens after your attempt
Correct Answer
B. (y=0x+9)
Step 1
Concept
With slope (0), the coefficient of (x) is (0). With (y)-intercept (9), we get (y=0x+9).
Step 2
Why this answer is correct
The correct answer is B. (y=0x+9). With slope (0), the coefficient of (x) is (0). With (y)-intercept (9), we get (y=0x+9).
Step 3
Exam Tip
ढाल (0) होने पर (x) का गुणांक (0) होगा। (y)-अवरोध (9) से (y=0x+9) मिलता है।
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कौन सी रेखा (y)-अवरोध (0) और ढाल (-6) रखती है?
Which line has (y)-intercept (0) and slope (-6)?
#origin
#negative_slope
#equation_selection
A (y=-6x)
B (y=6x)
C (y=-6)
D (y=x-6)
Explanation opens after your attempt
Correct Answer
A. (y=-6x)
Step 1
Concept
(y)-intercept (0) means there is no constant term. With slope (-6), the line is (y=-6x).
Step 2
Why this answer is correct
The correct answer is A. (y=-6x). (y)-intercept (0) means there is no constant term. With slope (-6), the line is (y=-6x).
Step 3
Exam Tip
(y)-अवरोध (0) का अर्थ स्थिर पद नहीं है। ढाल (-6) होने से (y=-6x) है।
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