equation_selection se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
22 questions tagged with equation_selection.
Which line gives (y=-10) at (x=0) and has slope (8)?
A. (y=8x-10)
(x=0) पर (y=-10) का अर्थ (c=-10) है। ढाल (8) से रेखा (y=8x-10) है। / (y=-10) at (x=0) means (c=-10). With slope (8), the line is (y=8x-10).
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Which line gives (y=15) at (x=0) and has slope (-3)?
B. (y=-3x+15)
(x=0) पर (y=15) से (c=15) मिलता है। ढाल (-3) होने से (y=-3x+15) सही है। / At (x=0), (y=15) gives (c=15). With slope (-3), (y=-3x+15) is correct.
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The line (y=6x+b) has (y)-intercept (13). Which equation is correct?
C. (y=6x+13)
(b) (y)-अवरोध है। (b=13) रखने पर (y=6x+13) बनता है। / (b) is the (y)-intercept. Putting (b=13) gives (y=6x+13).
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The line (y=ax-5) has slope (-7). Which equation is correct?
B. (y=-7x-5)
ढाल (a) के बराबर है। (a=-7) रखने पर (y=-7x-5) मिलता है। / The slope equals (a). Putting (a=-7) gives (y=-7x-5).
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Which line passes through the origin and has slope (11)?
A. (y=11x)
मूल बिंदु से गुजरने पर (y)-अवरोध (0) होता है। ढाल (11) होने से (y=11x) सही है। / Passing through the origin means the (y)-intercept is (0). With slope (11), (y=11x) is correct.
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Which line has slope (0) and (y)-intercept (-8)?
B. (y=0x-8)
ढाल (0) होने पर (x) का गुणांक (0) होगा। (y)-अवरोध (-8) से (y=0x-8) है। / With slope (0), the coefficient of (x) is (0). With (y)-intercept (-8), the line is (y=0x-8).
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If a line has slope (-6) and (y=5) at (x=0), which line is it?
B. (y=-6x+5)
(x=0) पर (y=5) का अर्थ (y)-अवरोध (5) है। ढाल (-6) से (y=-6x+5) बनता है। / (y=5) at (x=0) means the (y)-intercept is (5). With slope (-6), the line is (y=-6x+5).
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If a line has slope (-10) and (y)-intercept (8), which equation is correct?
C. (y=-10x+8)
ढाल (x) का गुणांक और (y)-अवरोध स्थिर पद होता है। इसलिए (y=-10x+8) सही है। / The slope is the coefficient of (x) and the (y)-intercept is the constant term. So (y=-10x+8) is correct.
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Which line gives (y=-8) at (x=0) and has slope (6)?
A. (y=6x-8)
(x=0) पर (y=-8) का अर्थ (c=-8) है। ढाल (6) से रेखा (y=6x-8) है। / (y=-8) at (x=0) means (c=-8). With slope (6), the line is (y=6x-8).
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Which line gives (y=12) at (x=0) and has slope (-4)?
B. (y=-4x+12)
(x=0) पर (y=12) से (c=12) मिलता है। ढाल (-4) होने से (y=-4x+12) सही है। / At (x=0), (y=12) gives (c=12). With slope (-4), (y=-4x+12) is correct.
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The line (y=4x+b) has (y)-intercept (11). Which equation is correct?
C. (y=4x+11)
(b) (y)-अवरोध है। (b=11) रखने पर (y=4x+11) बनता है। / (b) is the (y)-intercept. Putting (b=11) gives (y=4x+11).
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The line (y=ax-3) has slope (-6). Which equation is correct?
B. (y=-6x-3)
ढाल (a) के बराबर है। (a=-6) रखने पर (y=-6x-3) मिलता है। / The slope equals (a). Putting (a=-6) gives (y=-6x-3).
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Which line passes through the origin and has slope (9)?
A. (y=9x)
मूल बिंदु से गुजरने पर (y)-अवरोध (0) होता है। ढाल (9) होने से (y=9x) सही है। / Passing through the origin means the (y)-intercept is (0). With slope (9), (y=9x) is correct.
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Which line has slope (0) and (y)-intercept (-4)?
B. (y=0x-4)
ढाल (0) होने पर (x) का गुणांक (0) होगा। (y)-अवरोध (-4) से (y=0x-4) है। / With slope (0), the coefficient of (x) is (0). With (y)-intercept (-4), the line is (y=0x-4).
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If a line has slope (-5) and (y=3) at (x=0), which line is it?
B. (y=-5x+3)
(x=0) पर (y=3) का अर्थ (y)-अवरोध (3) है। ढाल (-5) से (y=-5x+3) बनता है। / (y=3) at (x=0) means the (y)-intercept is (3). With slope (-5), the line is (y=-5x+3).
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If a line has slope (-8) and (y)-intercept (5), which equation is correct?
C. (y=-8x+5)
ढाल (x) का गुणांक और (y)-अवरोध स्थिर पद होता है। इसलिए (y=-8x+5) सही है। / The slope is the coefficient of (x) and the (y)-intercept is the constant term. So (y=-8x+5) is correct.
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Which line gives (y=-2) at (x=0) and has slope (-5)?
C. (y=-5x-2)
(x=0) पर (y=-2) से (c=-2) मिलता है। ढाल (-5) होने से (y=-5x-2) सही है। / At (x=0), (y=-2) gives (c=-2). With slope (-5), (y=-5x-2) is correct.
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Which line gives (y=4) at (x=0) and has slope (3)?
A. (y=3x+4)
(x=0) पर (y=4) का अर्थ (y)-अवरोध (4) है। ढाल (3) से रेखा (y=3x+4) है। / (y=4) at (x=0) means the (y)-intercept is (4). With slope (3), the line is (y=3x+4).
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The line (y=-2x+b) has (y)-intercept (-6). Which equation is correct?
B. (y=-2x-6)
(b) ही (y)-अवरोध है। (b=-6) रखने पर (y=-2x-6) बनता है। / (b) is the (y)-intercept. Putting (b=-6) gives (y=-2x-6).
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The line (y=ax+4) has slope (9). Which equation is correct?
A. (y=9x+4)
ढाल (a) के बराबर है। (a=9) रखने पर (y=9x+4) मिलता है। / The slope equals (a). Putting (a=9) gives (y=9x+4).
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Which line has slope (0) and (y)-intercept (9)?
B. (y=0x+9)
ढाल (0) होने पर (x) का गुणांक (0) होगा। (y)-अवरोध (9) से (y=0x+9) मिलता है। / With slope (0), the coefficient of (x) is (0). With (y)-intercept (9), we get (y=0x+9).
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Which line has (y)-intercept (0) and slope (-6)?
A. (y=-6x)
(y)-अवरोध (0) का अर्थ स्थिर पद नहीं है। ढाल (-6) होने से (y=-6x) है। / (y)-intercept (0) means there is no constant term. With slope (-6), the line is (y=-6x).
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