फलन (f(x)=\sqrt{16-x-2}) का वास्तविक डोमेन क्या है?
What is the real domain of (f(x)=\sqrt{16-x-2})?
Explanation opens after your attempt
Correct Answer
A. ([-4,4])
Concept
For a real square root, \(16-x^2\ge 0\) is required. This gives \(x^2\le 16\) and the domain ([-4,4]).
Why this answer is correct
The correct answer is A. ([-4,4]). For a real square root, \(16-x^2\ge 0\) is required. This gives \(x^2\le 16\) and the domain ([-4,4]).
Exam Tip
वास्तविक वर्गमूल के लिए \(16-x^2\ge 0\) चाहिए। इससे \(x^2\le 16\) और डोमेन ([-4,4]) मिलता है।
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