Concept-wise Practice

domain-check MCQ Questions for Class 12

domain-check se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with domain-check.

कौन सा व्यंजक वास्तविक संख्या के रूप में परिभाषित है?

Which expression is defined as a real number?

Explanation opens after your attempt
Correct Answer

C. \(\tan^{-1}5\)

Step 1

Concept

The function \(\tan^{-1}x\) is defined for every real (x). In the other options the domain condition fails.

Step 2

Why this answer is correct

The correct answer is C. \(\tan^{-1}5\). The function \(\tan^{-1}x\) is defined for every real (x). In the other options the domain condition fails.

Step 3

Exam Tip

\(\tan^{-1}x\) सभी वास्तविक (x) के लिए परिभाषित है। बाकी विकल्पों में प्रांत की शर्त टूटती है।

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कौन सा व्यंजक वास्तविक संख्या नहीं देता?

Which expression does not give a real number?

Explanation opens after your attempt
Correct Answer

A. (\cos^{-1}\left\(\frac{7}{6}\right\))

Step 1

Concept

The expression \(\cos^{-1}x\) is real only for \(x\in[-1,1]\), and \(\frac{7}{6}>1\). Hence it will not give a real value.

Step 2

Why this answer is correct

The correct answer is A. (\cos^{-1}\left\(\frac{7}{6}\right\)). The expression \(\cos^{-1}x\) is real only for \(x\in[-1,1]\), and \(\frac{7}{6}>1\). Hence it will not give a real value.

Step 3

Exam Tip

\(\cos^{-1}x\) केवल \(x\in[-1,1]\) पर वास्तविक है और \(\frac{7}{6}>1\) है। इसलिए यह वास्तविक मान नहीं देगा।

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कौन सा व्यंजक परिभाषित है?

Which expression is defined?

Explanation opens after your attempt
Correct Answer

A. (\cos^{-1}(-1))

Step 1

Concept

Since \(-1\in[-1,1]\), (\cos^{-1}(-1)) is defined. The other options are outside their domains.

Step 2

Why this answer is correct

The correct answer is A. (\cos^{-1}(-1)). Since \(-1\in[-1,1]\), (\cos^{-1}(-1)) is defined. The other options are outside their domains.

Step 3

Exam Tip

\(-1\in[-1,1]\) इसलिए (\cos^{-1}(-1)) परिभाषित है। अन्य विकल्प अपने डोमेन से बाहर हैं।

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कौन सा व्यंजक परिभाषित नहीं है?

Which expression is not defined?

Explanation opens after your attempt
Correct Answer

A. \(\sin^{-1}2\)

Step 1

Concept

The expression \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\), and \(2\notin[-1,1]\). In domain questions check each option quickly.

Step 2

Why this answer is correct

The correct answer is A. \(\sin^{-1}2\). The expression \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\), and \(2\notin[-1,1]\). In domain questions check each option quickly.

Step 3

Exam Tip

\(\sin^{-1}x\) केवल \(x\in[-1,1]\) के लिए परिभाषित है और \(2\notin[-1,1]\)। डोमेन आधारित प्रश्नों में विकल्प तुरंत जांचें।

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