Concept-wise Practice

cubic factorization MCQ Questions for Class 10

cubic factorization se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

7 questions tagged with cubic factorization.

यदि (p(x)=x-3-12x-2+35x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-12x-2+35x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,5,7)

Step 1

Concept

(x-3-12x-2+35x=x(x-5)(x-7)), so the zeroes are (0), (5), (7). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,5,7). (x-3-12x-2+35x=x(x-5)(x-7)), so the zeroes are (0), (5), (7). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-12x-2+35x=x(x-5)(x-7)) है, इसलिए शून्यक (0), (5), (7) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-3-9x-2+18x) है, तो ग्राफ के शून्यकों का माध्य क्या है?

If (p(x)=x-3-9x-2+18x), what is the mean of the zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

(p(x)=x(x-3)(x-6)), so the zeroes are (0), (3), (6), and the mean is (3). Tip: factor first.

Step 2

Why this answer is correct

The correct answer is A. (3). (p(x)=x(x-3)(x-6)), so the zeroes are (0), (3), (6), and the mean is (3). Tip: factor first.

Step 3

Exam Tip

(p(x)=x(x-3)(x-6)) है इसलिए शून्यक (0), (3), (6) और माध्य (3) है। टिप: पहले गुणनखंड करें।

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यदि (p(x)=x-3-10x-2+24x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-10x-2+24x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,4,6)

Step 1

Concept

(x-3-10x-2+24x=x(x-4)(x-6)), so the zeroes are (0), (4), (6). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,4,6). (x-3-10x-2+24x=x(x-4)(x-6)), so the zeroes are (0), (4), (6). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-10x-2+24x=x(x-4)(x-6)) है, इसलिए शून्यक (0), (4), (6) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-3-7x-2+10x) है, तो ग्राफ के शून्यकों का माध्य क्या है?

If (p(x)=x-3-7x-2+10x), what is the mean of the zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. \(\frac{7}{3}\)

Step 1

Concept

(p(x)=x(x-5)(x-2)), so the zeroes are (0), (2), (5), and the mean is \(\frac{7}{3}\). Tip: factor first.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{7}{3}\). (p(x)=x(x-5)(x-2)), so the zeroes are (0), (2), (5), and the mean is \(\frac{7}{3}\). Tip: factor first.

Step 3

Exam Tip

(p(x)=x(x-5)(x-2)) है, इसलिए शून्यक (0), (2), (5) और माध्य \(\frac{7}{3}\) है। टिप: पहले गुणनखंड करें।

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यदि (p(x)=x-3-8x-2+15x) है तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-8x-2+15x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,3,5)

Step 1

Concept

(x-3-8x-2+15x=x(x-3)(x-5)), so the zeroes are (0,3,5). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,3,5). (x-3-8x-2+15x=x(x-3)(x-5)), so the zeroes are (0,3,5). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-8x-2+15x=x(x-3)(x-5)) है इसलिए शून्यक (0,3,5) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-3-6x-2+5x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-6x-2+5x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,1,5)

Step 1

Concept

(x-3-6x-2+5x=x(x-1)(x-5)), so the zeroes are (0,1,5). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,1,5). (x-3-6x-2+5x=x(x-1)(x-5)), so the zeroes are (0,1,5). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-6x-2+5x=x(x-1)(x-5)) है, इसलिए शून्यक (0,1,5) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-3-4x-2-5x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-4x-2-5x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0, -1, 5)

Step 1

Concept

(x-3-4x-2-5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0, -1, 5). (x-3-4x-2-5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-4x-2-5x=x(x-5)(x+1)), इसलिए शून्यक (0), (5), (-1) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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