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If (p(x)=x^3-4x^2-5x), what is the set of zeroes of the graph?

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Answer and explanation

Correct answer: (0, -1, 5)

(x^3-4x^2-5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.

Related tags

Cubic FactorizationZeroesGraph

Frequently asked questions

What is the correct answer to this question?

(0, -1, 5)

Why is this the correct answer?

(x^3-4x^2-5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..

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