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Question 1/1 Expert Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 64

एक समान्तर श्रेणी में \(a_4+a_9=95\) और \(a_{16}=137\) है। \(a_{31}\) क्या होगा?

In an AP, \(a_4+a_9=95\) and \(a_{16}=137\). What is \(a_{31}\)?

Explanation opens after your attempt
Correct Answer

A. (263)

Step 1

Concept

(2a+11d=95) and (a+15d=137). Solving gives (d=9) and \(a_{31}=263\).

Step 2

Why this answer is correct

The correct answer is A. (263). (2a+11d=95) and (a+15d=137). Solving gives (d=9) and \(a_{31}=263\).

Step 3

Exam Tip

(2a+11d=95) और (a+15d=137)। हल करने पर (d=9) और \(a_{31}=263\)।

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