एक समान्तर श्रेणी में \(a_7+a_{21}=224\) और \(a_{13}+a_{27}=368\) है। \(a_{41}\) क्या होगा?
In an AP, \(a_7+a_{21}=224\) and \(a_{13}+a_{27}=368\). What is \(a_{41}\)?
Explanation opens after your attempt
Correct Answer
D. (560)
Concept
The first sum gives (2a+26d=224) and the second gives (2a+38d=368). (d=12) and \(a_{41}=560\).
Why this answer is correct
The correct answer is D. (560). The first sum gives (2a+26d=224) and the second gives (2a+38d=368). (d=12) and \(a_{41}=560\).
Exam Tip
पहले योग से (2a+26d=224) और दूसरे से (2a+38d=368)। (d=12) और \(a_{41}=560\)।
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