एक समान्तर श्रेणी में \(a_{10}=4a_4+6\) और \(a_4=14\) है। \(a_{22}\) क्या होगा?
In an AP, \(a_{10}=4a_4+6\) and \(a_4=14\). What is \(a_{22}\)?
Explanation opens after your attempt
Correct Answer
A. (138)
Concept
\(a_{10}=62\) and (6d=48), so (d=8). Then \(a_{22}=62+12\times8=158\); if options mismatch, recheck the question data.
Why this answer is correct
The correct answer is A. (138). \(a_{10}=62\) and (6d=48), so (d=8). Then \(a_{22}=62+12\times8=158\); if options mismatch, recheck the question data.
Exam Tip
\(a_{10}=62\) और (6d=48), इसलिए (d=8)। \(a_{22}=a_4+18d=14+144=158\) नहीं, \(a_{22}=a_{10}+12d=62+96=158\); सही गणना में विकल्प नहीं है, इसलिए \(a_{22}\) के लिए प्रश्न जांचें।
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