एक समान्तर श्रेणी में \(a_{15}=4a_7-10\) और \(a_7=26\) है। \(a_{31}\) क्या होगा?
In an AP, \(a_{15}=4a_7-10\) and \(a_7=26\). What is \(a_{31}\)?
Explanation opens after your attempt
B. (178)
Concept
\(a_{15}=94\) and (8d=68), so \(d=\frac{17}{2}\). \(a_{31}=94+16\cdot\frac{17}{2}=230\).
Why this answer is correct
The correct answer is B. (178). \(a_{15}=94\) and (8d=68), so \(d=\frac{17}{2}\). \(a_{31}=94+16\cdot\frac{17}{2}=230\).
Exam Tip
\(a_{15}=94\) और (8d=68) इसलिए \(d=\frac{17}{2}\)। \(a_{31}=94+16\cdot\frac{17}{2}=230\)।
Login to save your score, XP, coins and progress.
AI Video Prompt 16:9 + 9:16
Is question ka premium MCQ video banane ke liye ready prompt. Copy karke Sora, Runway, Canva AI, CapCut AI, ChatGPT video workflow ya editor me use karein.
