एक समान्तर श्रेणी में \(a_{10}=25\) और \(a_{30}=-135\) है। \(a_{55}\) क्या होगा?
In an AP, \(a_{10}=25\) and \(a_{30}=-135\). What is \(a_{55}\)?
Explanation opens after your attempt
Correct Answer
B. (-335)
Concept
\(d=\frac{-135-25}{30-10}=-8\). (a_{55}=-135+25(-8)=-335).
Why this answer is correct
The correct answer is B. (-335). \(d=\frac{-135-25}{30-10}=-8\). (a_{55}=-135+25(-8)=-335).
Exam Tip
\(d=\frac{-135-25}{30-10}=-8\)। (a_{55}=-135+25(-8)=-335)।
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