यदि \(a_n=an+b\), \(a_8=71\) और \(a_{26}=233\) है, तो \(a_{44}\) क्या होगा?
If \(a_n=an+b\), \(a_8=71\) and \(a_{26}=233\), what is \(a_{44}\)?
Explanation opens after your attempt
Correct Answer
C. (395)
Concept
(18a=162), so (a=9). \(a_{44}=a_{26}+18\times9=395\).
Why this answer is correct
The correct answer is C. (395). (18a=162), so (a=9). \(a_{44}=a_{26}+18\times9=395\).
Exam Tip
(18a=162), इसलिए (a=9)। \(a_{44}=a_{26}+18\times9=395\)।
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