एक समान्तर श्रेणी में \(a_4+a_{16}=86\) और \(a_{10}=43\) है। \(a_{25}\) ज्ञात कीजिए जब सार्व अंतर (5) है।
In an AP, \(a_4+a_{16}=86\) and \(a_{10}=43\). Find \(a_{25}\) when the common difference is (5).
Explanation opens after your attempt
Correct Answer
B. (118)
Concept
\(a_{25}=a_{10}+15d=43+75=118\). Do not get confused by extra information.
Why this answer is correct
The correct answer is B. (118). \(a_{25}=a_{10}+15d=43+75=118\). Do not get confused by extra information.
Exam Tip
\(a_{25}=a_{10}+15d=43+75=118\)। अनावश्यक जानकारी देखकर भ्रमित न हों।
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