एक AP में \(a_{16}=4a_7+2\) और \(a_7=22\) है। \(a_{34}\) क्या होगा?
In an AP \(a_{16}=4a_7+2\) and \(a_7=22\). What is \(a_{34}\)?
Explanation opens after your attempt
A. (224)
Concept
\(a_{16}=90\) and (9d=68) so \(d=\frac{68}{9}\). \(a_{34}=22+27\cdot\frac{68}{9}=226\).
Why this answer is correct
The correct answer is A. (224). \(a_{16}=90\) and (9d=68) so \(d=\frac{68}{9}\). \(a_{34}=22+27\cdot\frac{68}{9}=226\).
Exam Tip
\(a_{16}=90\) और (9d=68) इसलिए \(d=\frac{68}{9}\)। \(a_{34}=a_{16}+18d=90+136=226\) नहीं बल्कि \(a_{34}=22+27\cdot\frac{68}{9}=226\) होगा।
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