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In an arithmetic progression, a₁₂ = 3a₅ + 4 and a₅ = 19. What is a₂₆?एक समान्तर श्रेणी में a₁₂ = 3a₅ + 4 और a₅ = 19 है। a₂₆ का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 145145
First, a₁₂ = 3 × 19 + 4 = 61. Since a₁₂ − a₅ = 7d, we get 61 − 19 = 7d, so d = 6. Therefore, a₂₆ = a₅ + 21d = 19 + 21 × 6 = 145.पहले, a₁₂ = 3 × 19 + 4 = 61। चूँकि a₁₂ − a₅ = 7d, इसलिए 61 − 19 = 7d और d = 6। अतः a₂₆ = a₅ + 21d = 19 + 21 × 6 = 145।
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