एक समान्तर श्रेणी में \(a_{29}=a_{12}+255\) और \(a_{12}=86\) है। \(a_{72}\) क्या होगा?
In an AP \(a_{29}=a_{12}+255\) and \(a_{12}=86\). What is \(a_{72}\)?
Explanation opens after your attempt
B. (986)
Concept
(17d=255), so (d=15). \(a_{72}=a_{12}+60d=86+900=986\).
Why this answer is correct
The correct answer is B. (986). (17d=255), so (d=15). \(a_{72}=a_{12}+60d=86+900=986\).
Exam Tip
(17d=255), इसलिए (d=15)। \(a_{72}=a_{12}+60d=86+900=986\)।
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