यदि \(a_{10}=x+31\) और \(a_{27}=x+167\) है, तो \(a_{44}\) (x) के रूप में क्या होगा?
If \(a_{10}=x+31\) and \(a_{27}=x+167\), what is \(a_{44}\) in terms of (x)?
Explanation opens after your attempt
C. (x+303)
Concept
From (17d=136), (d=8). \(a_{44}=x+167+17\times8=x+303\).
Why this answer is correct
The correct answer is C. (x+303). From (17d=136), (d=8). \(a_{44}=x+167+17\times8=x+303\).
Exam Tip
(17d=136) से (d=8)। \(a_{44}=x+167+17\times8=x+303\)।
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