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ap-distractor-hard MCQ Questions for Class 10

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Question 1/1 Hard Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 64

यदि \(a_1=12\) और \(a_{n}=3a_{n-1}+2\) नहीं बल्कि AP का (a_n=12+(n-1)d) है तथा \(a_9=68\) है तो \(a_{22}\) क्या होगा?

If \(a_1=12\) and it is not \(a_n=3a_{n-1}+2\) but an AP with (a_n=12+(n-1)d), and \(a_9=68\), what is \(a_{22}\)?

Explanation opens after your attempt

Correct Answer

A. (159)

Step 1

Concept

From (68=12+8d), (d=7). Therefore \(a_{22}=12+21\times7=159\).

Step 2

Why this answer is correct

The correct answer is A. (159). From (68=12+8d), (d=7). Therefore \(a_{22}=12+21\times7=159\).

Step 3

Exam Tip

(68=12+8d) से (d=7)। इसलिए \(a_{22}=12+21\times7=159\)।

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