4 results found for "ratio_of_roots" in Class 10.
Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि \(x^2+px+18=0\) के मूलों का अनुपात (1:2) है और दोनों ऋणात्मक हैं तो (p) क्या होगा?
If roots of \(x^2+px+18=0\) are in the ratio (1:2) and both are negative, what is (p)?
Explanation opens after your attempt
Step 1
Concept
The roots are (-3) and (-6) because the product is (18). Their sum is (-9), so (p=9).
Step 2
Why this answer is correct
The correct answer is A. (9). The roots are (-3) and (-6) because the product is (18). Their sum is (-9), so (p=9).
Step 3
Exam Tip
मूल (-3) और (-6) होंगे क्योंकि गुणनफल (18) है। उनका योग (-9) है इसलिए (p=9) है।
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Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि \(x^2-9x+c=0\) के मूलों का अनुपात (1:2) है तो (c) का मान क्या है?
If the roots of \(x^2-9x+c=0\) are in the ratio (1:2), what is the value of (c)?
Explanation opens after your attempt
Step 1
Concept
Let the roots be (t) and (2t). From (3t=9), (t=3), so the roots are (3) and (6), hence (c=18).
Step 2
Why this answer is correct
The correct answer is A. (18). Let the roots be (t) and (2t). From (3t=9), (t=3), so the roots are (3) and (6), hence (c=18).
Step 3
Exam Tip
मूल (t) और (2t) मानें तो (3t=9) से (t=3) है। मूल (3) और (6) होंगे इसलिए (c=18) है।
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Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि \(x^2+px+12=0\) के मूलों का अनुपात (1:3) है और दोनों ऋणात्मक हैं तो (p) क्या होगा?
If roots of \(x^2+px+12=0\) are in the ratio (1:3) and both are negative, what is (p)?
Explanation opens after your attempt
Step 1
Concept
The roots are (-2) and (-6) because the product is (12). Their sum is (-8), so (-p=-8) gives (p=8).
Step 2
Why this answer is correct
The correct answer is A. (8). The roots are (-2) and (-6) because the product is (12). Their sum is (-8), so (-p=-8) gives (p=8).
Step 3
Exam Tip
मूल (-2) और (-6) होंगे क्योंकि गुणनफल (12) है। उनका योग (-8) है इसलिए (-p=-8) से (p=8) है।
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Question
Hard Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि \(x^2-6x+c=0\) के मूलों का अनुपात (1:2) है तो (c) का मान क्या है?
If the roots of \(x^2-6x+c=0\) are in the ratio (1:2), what is the value of (c)?
Explanation opens after your attempt
Step 1
Concept
Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).
Step 2
Why this answer is correct
The correct answer is A. (8). Let the roots be (t) and (2t). From sum (3t=6), (t=2), so roots are (2) and (4), hence (c=8).
Step 3
Exam Tip
मूल (t) और (2t) मानें तो योग (3t=6) से (t=2) है। मूल (2) और (4) होंगे इसलिए (c=8) है।
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