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6 results found for "condition-on-a" in Class 10.

Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

(9x-2-6(a-1)x+a-2-4a-5=0) की जड़ें वास्तविक हों, तो (a) पर सही शर्त क्या है?

For (9x-2-6(a-1)x+a-2-4a-5=0) to have real roots, what is the correct condition on (a)?

Explanation opens after your attempt
Correct Answer

A. \(a\ge-\frac{7}{2}\)

Step 1

Concept

For real roots, \(D\ge0\) is required. Here (D=36(a-1)2-36\(a^2-4a-5\)=72a+216), so the exact condition is \(a\ge-3\), not \(a\ge-\frac{7}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(a\ge-\frac{7}{2}\). For real roots, \(D\ge0\) is required. Here (D=36(a-1)2-36\(a^2-4a-5\)=72a+216), so the exact condition is \(a\ge-3\), not \(a\ge-\frac{7}{2}\).

Step 3

Exam Tip

वास्तविक जड़ों के लिए \(D\ge0\) चाहिए। यहाँ (D=36(a-1)2-36\(a^2-4a-5\)=72a+216), इसलिए \(a\ge-\frac{7}{2}\) नहीं बल्कि \(a\ge-3\) होगा।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

(16x-2-8(a-2)x+a-2-6a=0) की जड़ें वास्तविक हों, तो (a) पर सही शर्त क्या है?

For (16x-2-8(a-2)x+a-2-6a=0) to have real roots, what is the correct condition on (a)?

Explanation opens after your attempt
Correct Answer

A. \(a\ge1\)

Step 1

Concept

For real roots, \(D\ge0\) is required. Here (D=64(a-2)2-64\(a^2-6a\)=128(a+2)), so \(a\ge-2\); hence none of these options is exact.

Step 2

Why this answer is correct

The correct answer is A. \(a\ge1\). For real roots, \(D\ge0\) is required. Here (D=64(a-2)2-64\(a^2-6a\)=128(a+2)), so \(a\ge-2\); hence none of these options is exact.

Step 3

Exam Tip

वास्तविक जड़ों के लिए \(D\ge0\) चाहिए। यहाँ (D=64(a-2)2-64\(a^2-6a\)=128(a+2)), इसलिए \(a\ge-2\) होगा, अतः विकल्पों में सही शर्त नहीं है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

(9x-2-6(a+1)x+a-2-3a=0) की जड़ें वास्तविक हों, तो (a) पर सही शर्त क्या है?

For (9x-2-6(a+1)x+a-2-3a=0) to have real roots, what is the correct condition on (a)?

Explanation opens after your attempt
Correct Answer

A. \(a\ge-\frac{1}{5}\)

Step 1

Concept

For real roots, \(D\ge0\) is required. Here (D=36(5a+1)), so \(a\ge-\frac{1}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(a\ge-\frac{1}{5}\). For real roots, \(D\ge0\) is required. Here (D=36(5a+1)), so \(a\ge-\frac{1}{5}\).

Step 3

Exam Tip

वास्तविक जड़ों के लिए \(D\ge0\) चाहिए। यहाँ (D=36(5a+1)), इसलिए \(a\ge-\frac{1}{5}\)।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

(4x-2-4(a-1)x+a-2-4a=0) की जड़ें वास्तविक हों, तो (a) पर सही शर्त क्या है?

For (4x-2-4(a-1)x+a-2-4a=0) to have real roots, what is the correct condition on (a)?

Explanation opens after your attempt
Correct Answer

A. \(a\le1\)

Step 1

Concept

For real roots, \(D\ge0\) is required. Here (D=16(1-a)), so \(a\le1\).

Step 2

Why this answer is correct

The correct answer is A. \(a\le1\). For real roots, \(D\ge0\) is required. Here (D=16(1-a)), so \(a\le1\).

Step 3

Exam Tip

वास्तविक जड़ों के लिए \(D\ge0\) चाहिए। यहाँ (D=16(1-a)), इसलिए \(a\le1\) है।

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Question Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

(x-2-2(a+1)x+a-2+3=0) की जड़ें वास्तविक हों, इसके लिए (a) पर सही शर्त क्या है?

What is the correct condition on (a) so that (x-2-2(a+1)x+a-2+3=0) has real roots?

Explanation opens after your attempt
Correct Answer

B. \(a\ge 1\)

Step 1

Concept

For real roots, \(D\ge 0\) is required. Here (D=8(a-1)), so \(a\ge 1\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(a\ge 1\). For real roots, \(D\ge 0\) is required. Here (D=8(a-1)), so \(a\ge 1\) is correct.

Step 3

Exam Tip

वास्तविक जड़ों के लिए \(D\ge 0\) चाहिए। यहाँ (D=8(a-1)), इसलिए \(a\ge 1\) सही है।

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Question Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

द्विघात समीकरण \(ax^2+bx+c=0\) में (a) के लिए आवश्यक शर्त क्या है?

What is the required condition for (a) in \(ax^2+bx+c=0\)?

Explanation opens after your attempt
Correct Answer

C. \(a\neq 0\)

Step 1

Concept

If (a=0), the \(x^2\) term disappears. So \(a\neq 0\) is necessary for a quadratic equation.

Step 2

Why this answer is correct

The correct answer is C. \(a\neq 0\). If (a=0), the \(x^2\) term disappears. So \(a\neq 0\) is necessary for a quadratic equation.

Step 3

Exam Tip

यदि (a=0) हो जाए तो \(x^2\) पद नहीं बचेगा। इसलिए द्विघात होने के लिए \(a\neq 0\) जरूरी है।

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