(4x-2-4(a-1)x+a-2-4a=0) की जड़ें वास्तविक हों, तो (a) पर सही शर्त क्या है?
For (4x-2-4(a-1)x+a-2-4a=0) to have real roots, what is the correct condition on (a)?
Explanation opens after your attempt
Correct Answer
A. \(a\le1\)
Concept
For real roots, \(D\ge0\) is required. Here (D=16(1-a)), so \(a\le1\).
Why this answer is correct
The correct answer is A. \(a\le1\). For real roots, \(D\ge0\) is required. Here (D=16(1-a)), so \(a\le1\).
Exam Tip
वास्तविक जड़ों के लिए \(D\ge0\) चाहिए। यहाँ (D=16(1-a)), इसलिए \(a\le1\) है।
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