(9x-2-6(a+1)x+a-2-3a=0) की जड़ें वास्तविक हों, तो (a) पर सही शर्त क्या है?
For (9x-2-6(a+1)x+a-2-3a=0) to have real roots, what is the correct condition on (a)?
Explanation opens after your attempt
Correct Answer
A. \(a\ge-\frac{1}{5}\)
Concept
For real roots, \(D\ge0\) is required. Here (D=36(5a+1)), so \(a\ge-\frac{1}{5}\).
Why this answer is correct
The correct answer is A. \(a\ge-\frac{1}{5}\). For real roots, \(D\ge0\) is required. Here (D=36(5a+1)), so \(a\ge-\frac{1}{5}\).
Exam Tip
वास्तविक जड़ों के लिए \(D\ge0\) चाहिए। यहाँ (D=36(5a+1)), इसलिए \(a\ge-\frac{1}{5}\)।
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