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Class 12 · Mathematics

If (f:\mathbb{R}\to[-1,\infty)), (f(x)=x^2-1), what is the correct statement about (f)?

Class 12 · Mathematics

If (f:\mathbb{R}\to{0,1}), (f(x)=1) for every (x), why is (f) not onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to{0,1}), (f(x)=0) when (x<0) and (f(x)=1) when (x\ge0), what is correct about (f)?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=\lceil x\rceil), why is (f) not onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{Z}), (f(x)=\lceil x\rceil), which option is correct?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{Z}), (f(x)=\lfloor x\rfloor), what is the correct statement about (f)?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=\lfloor x\rfloor), is (f) onto or not?

Class 12 · Mathematics

If (f:[0,\infty)\to[1,\infty)), (f(x)=\sqrt{x}+1), what is the correct statement?

Class 12 · Mathematics

If (f:[0,\infty)\to\mathbb{R}), (f(x)=\sqrt{x}+1), why is it not onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=\sqrt[3]{x}+2), choose the correct option about (f).

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=\sqrt{x^2}), why is it not onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to[0,\infty)), (f(x)=\sqrt{x^2}), what is the correct statement about (f)?

Class 12 · Mathematics

If (f:{1,3,5}\to{0,1}), where (f(n)) is (0) when (n) is even and (1) when (n) is odd, why is (f) not onto?

Class 12 · Mathematics

If (f:{1,2,3,4,5}\to{0,1}), where (f(n)) is (0) when (n) is even and (1) when (n) is odd, what is correct about (f)?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=|x-2|+1), why is it not onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to[1,\infty)), (f(x)=|x-2|+1), choose the correct option.

Class 12 · Mathematics

If (f:\mathbb{R}\to[0,\infty)), (f(x)=x^4+x^2), what is the correct statement about (f)?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=x^4+x^2), why is it not onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to\mathbb{R}), (f(x)=x^3-5x), what is a simple reason that (f) is onto?

Class 12 · Mathematics

If (f:\mathbb{R}\to[-1,1]), (f(x)=\frac{x}{\sqrt{1+x^2}}), why is (f) not onto?