Hard Mathematics Polynomials Class 10 Level 28

किस बहुपद के शून्यक \(\sqrt{2}+\sqrt{3}\) और \(\sqrt{2}-\sqrt{3}\) हैं?

Which polynomial has zeroes \(\sqrt{2}+\sqrt{3}\) and \(\sqrt{2}-\sqrt{3}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-2\sqrt{2}x-1\)

Step 1

Concept

The sum is \(2\sqrt{2}\) and the product is (2-3=-1). Hence the polynomial is \(x^2-2\sqrt{2}x-1\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-2\sqrt{2}x-1\). The sum is \(2\sqrt{2}\) and the product is (2-3=-1). Hence the polynomial is \(x^2-2\sqrt{2}x-1\).

Step 3

Exam Tip

योग \(2\sqrt{2}\) और गुणनफल (2-3=-1) है। इसलिए बहुपद \(x^2-2\sqrt{2}x-1\) बनेगा।

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Mathematics Answer, Explanation and Revision Hints

किस बहुपद के शून्यक \(\sqrt{2}+\sqrt{3}\) और \(\sqrt{2}-\sqrt{3}\) हैं? / Which polynomial has zeroes \(\sqrt{2}+\sqrt{3}\) and \(\sqrt{2}-\sqrt{3}\)?

Correct Answer: A. \(x^2-2\sqrt{2}x-1\). Explanation: योग \(2\sqrt{2}\) और गुणनफल (2-3=-1) है। इसलिए बहुपद \(x^2-2\sqrt{2}x-1\) बनेगा। / The sum is \(2\sqrt{2}\) and the product is (2-3=-1). Hence the polynomial is \(x^2-2\sqrt{2}x-1\).

Which concept should I revise for this Mathematics MCQ?

The sum is \(2\sqrt{2}\) and the product is (2-3=-1). Hence the polynomial is \(x^2-2\sqrt{2}x-1\).

What exam hint can help solve this Mathematics question?

योग \(2\sqrt{2}\) और गुणनफल (2-3=-1) है। इसलिए बहुपद \(x^2-2\sqrt{2}x-1\) बनेगा।

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