Hard Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प (\sqrt{2}\times\(\sqrt{18}-\sqrt{8}\)) का मान है?

Which option is the value of (\sqrt{2}\times\(\sqrt{18}-\sqrt{8}\))?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

\(\sqrt{18}=3\sqrt{2}\) and \(\sqrt{8}=2\sqrt{2}\), so the bracket is \(\sqrt{2}\). The product is (2).

Step 2

Why this answer is correct

The correct answer is A. (2). \(\sqrt{18}=3\sqrt{2}\) and \(\sqrt{8}=2\sqrt{2}\), so the bracket is \(\sqrt{2}\). The product is (2).

Step 3

Exam Tip

\(\sqrt{18}=3\sqrt{2}\) और \(\sqrt{8}=2\sqrt{2}\), इसलिए कोष्ठक \(\sqrt{2}\) है। गुणनफल (2) है।

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Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प (\sqrt{2}\times\(\sqrt{18}-\sqrt{8}\)) का मान है? / Which option is the value of (\sqrt{2}\times\(\sqrt{18}-\sqrt{8}\))?

Correct Answer: A. (2). Explanation: \(\sqrt{18}=3\sqrt{2}\) और \(\sqrt{8}=2\sqrt{2}\), इसलिए कोष्ठक \(\sqrt{2}\) है। गुणनफल (2) है। / \(\sqrt{18}=3\sqrt{2}\) and \(\sqrt{8}=2\sqrt{2}\), so the bracket is \(\sqrt{2}\). The product is (2).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{18}=3\sqrt{2}\) and \(\sqrt{8}=2\sqrt{2}\), so the bracket is \(\sqrt{2}\). The product is (2).

What exam hint can help solve this Mathematics question?

\(\sqrt{18}=3\sqrt{2}\) और \(\sqrt{8}=2\sqrt{2}\), इसलिए कोष्ठक \(\sqrt{2}\) है। गुणनफल (2) है।

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