Hard Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प \(2\sqrt{12}-3\sqrt{27}+\sqrt{75}\) का सरल रूप है?

Which option is the simplified form of \(2\sqrt{12}-3\sqrt{27}+\sqrt{75}\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

It becomes \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\). First convert all roots to like radical form.

Step 2

Why this answer is correct

The correct answer is A. (0). It becomes \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\). First convert all roots to like radical form.

Step 3

Exam Tip

यह \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\) बनता है। पहले सभी जड़ों को समान रूप में बदलें।

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Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(2\sqrt{12}-3\sqrt{27}+\sqrt{75}\) का सरल रूप है? / Which option is the simplified form of \(2\sqrt{12}-3\sqrt{27}+\sqrt{75}\)?

Correct Answer: A. (0). Explanation: यह \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\) बनता है। पहले सभी जड़ों को समान रूप में बदलें। / It becomes \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\). First convert all roots to like radical form.

Which concept should I revise for this Mathematics MCQ?

It becomes \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\). First convert all roots to like radical form.

What exam hint can help solve this Mathematics question?

यह \(4\sqrt{3}-9\sqrt{3}+5\sqrt{3}=0\) बनता है। पहले सभी जड़ों को समान रूप में बदलें।

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