Medium Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प \(\sqrt{3}\) और \(\sqrt{27}\) का गुणनफल बताता है?

Which option gives the product of \(\sqrt{3}\) and \(\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). In multiplication multiply the numbers inside the roots.

Step 2

Why this answer is correct

The correct answer is A. (9). \(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). In multiplication multiply the numbers inside the roots.

Step 3

Exam Tip

\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\) है। गुणन में जड़ों के अंदर के संख्याओं को गुणा करें।

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Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(\sqrt{3}\) और \(\sqrt{27}\) का गुणनफल बताता है? / Which option gives the product of \(\sqrt{3}\) and \(\sqrt{27}\)?

Correct Answer: A. (9). Explanation: \(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\) है। गुणन में जड़ों के अंदर के संख्याओं को गुणा करें। / \(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). In multiplication multiply the numbers inside the roots.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). In multiplication multiply the numbers inside the roots.

What exam hint can help solve this Mathematics question?

\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\) है। गुणन में जड़ों के अंदर के संख्याओं को गुणा करें।

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