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Which is the root of \(x^2-18x+81=0\)?
A. (9) दो बार(9) twice
(x-2-18x+81=(x-9)2). Therefore the repeated root is (9).
The correct answer is A. (9) दो बार / (9) twice. (x-2-18x+81=(x-9)2). Therefore the repeated root is (9).
(x-2-18x+81=(x-9)2) है। इसलिए दोहराया मूल (9) है।
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Correct Answer: A. (9) दो बार / (9) twice. Explanation: (x-2-18x+81=(x-9)2) है। इसलिए दोहराया मूल (9) है। / (x-2-18x+81=(x-9)2). Therefore the repeated root is (9).
(x-2-18x+81=(x-9)2). Therefore the repeated root is (9).
(x-2-18x+81=(x-9)2) है। इसलिए दोहराया मूल (9) है।
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