Hard Mathematics Quadratic Equations Class 10 Level 29

किस समीकरण में मूल बराबर और धनात्मक होंगे?

Which equation will have equal and positive roots?

Explanation opens after your attempt
Correct Answer

A. \(x^2-12x+36=0\)

Step 1

Concept

(x-2-12x+36=(x-6)2), so both roots are (6). Both roots are equal and positive.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-12x+36=0\). (x-2-12x+36=(x-6)2), so both roots are (6). Both roots are equal and positive.

Step 3

Exam Tip

(x-2-12x+36=(x-6)2), इसलिए दोनों मूल (6) हैं। दोनों मूल बराबर और धनात्मक हैं।

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Mathematics Answer, Explanation and Revision Hints

किस समीकरण में मूल बराबर और धनात्मक होंगे? / Which equation will have equal and positive roots?

Correct Answer: A. \(x^2-12x+36=0\). Explanation: (x-2-12x+36=(x-6)2), इसलिए दोनों मूल (6) हैं। दोनों मूल बराबर और धनात्मक हैं। / (x-2-12x+36=(x-6)2), so both roots are (6). Both roots are equal and positive.

Which concept should I revise for this Mathematics MCQ?

(x-2-12x+36=(x-6)2), so both roots are (6). Both roots are equal and positive.

What exam hint can help solve this Mathematics question?

(x-2-12x+36=(x-6)2), इसलिए दोनों मूल (6) हैं। दोनों मूल बराबर और धनात्मक हैं।

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