किस समीकरण में मूल बराबर और धनात्मक होंगे?
Which equation will have equal and positive roots?
Explanation opens after your attempt
A. \(x^2-12x+36=0\)
Concept
(x-2-12x+36=(x-6)2), so both roots are (6). Both roots are equal and positive.
Why this answer is correct
The correct answer is A. \(x^2-12x+36=0\). (x-2-12x+36=(x-6)2), so both roots are (6). Both roots are equal and positive.
Exam Tip
(x-2-12x+36=(x-6)2), इसलिए दोनों मूल (6) हैं। दोनों मूल बराबर और धनात्मक हैं।
Login to save your score, XP, coins and progress.