Hard Mathematics Quadratic Equations Class 10 Level 30

किस समीकरण में मूल बराबर और ऋणात्मक होंगे?

Which equation will have equal and negative roots?

Explanation opens after your attempt
Correct Answer

A. \(x^2+16x+64=0\)

Step 1

Concept

(x-2+16x+64=(x+8)2), so both roots are (-8). Both roots are equal and negative.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+16x+64=0\). (x-2+16x+64=(x+8)2), so both roots are (-8). Both roots are equal and negative.

Step 3

Exam Tip

(x-2+16x+64=(x+8)2), इसलिए दोनों मूल (-8) हैं। दोनों मूल बराबर और ऋणात्मक हैं।

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किस समीकरण में मूल बराबर और ऋणात्मक होंगे? / Which equation will have equal and negative roots?

Correct Answer: A. \(x^2+16x+64=0\). Explanation: (x-2+16x+64=(x+8)2), इसलिए दोनों मूल (-8) हैं। दोनों मूल बराबर और ऋणात्मक हैं। / (x-2+16x+64=(x+8)2), so both roots are (-8). Both roots are equal and negative.

Which concept should I revise for this Mathematics MCQ?

(x-2+16x+64=(x+8)2), so both roots are (-8). Both roots are equal and negative.

What exam hint can help solve this Mathematics question?

(x-2+16x+64=(x+8)2), इसलिए दोनों मूल (-8) हैं। दोनों मूल बराबर और ऋणात्मक हैं।

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