कौन सा निष्कर्ष सही है यदि संख्या \(\sqrt{n}\) में (n) पूर्ण वर्ग नहीं है?
Which conclusion is correct if (n) is not a perfect square in the number \(\sqrt{n}\)?
Explanation opens after your attempt
A. \(\sqrt{n}\) अपरिमेय होगी\(\sqrt{n}\) will be irrational
Concept
If positive integer (n) is not a perfect square then \(\sqrt{n}\) is irrational. This is an easy exam rule.
Why this answer is correct
The correct answer is A. \(\sqrt{n}\) अपरिमेय होगी / \(\sqrt{n}\) will be irrational. If positive integer (n) is not a perfect square then \(\sqrt{n}\) is irrational. This is an easy exam rule.
Exam Tip
धनात्मक पूर्णांक (n) पूर्ण वर्ग न हो तो \(\sqrt{n}\) अपरिमेय होती है। यह आसान परीक्षा नियम है।
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