युग्म \(\alpha x+4y=7\) और (9x+12y=21) का अद्वितीय हल कब होगा?

When will \(\alpha x+4y=7\) and (9x+12y=21) have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(\alpha\neq3\)

Step 1

Concept

For a unique solution, \(\frac{\alpha}{9}\neq\frac{4}{12}\) must hold. Thus \(\alpha\neq3\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(\alpha\neq3\). For a unique solution, \(\frac{\alpha}{9}\neq\frac{4}{12}\) must hold. Thus \(\alpha\neq3\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(\frac{\alpha}{9}\neq\frac{4}{12}\) होना चाहिए। इसलिए \(\alpha\neq3\) सही शर्त है।

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Mathematics Answer, Explanation and Revision Hints

युग्म \(\alpha x+4y=7\) और (9x+12y=21) का अद्वितीय हल कब होगा? / When will \(\alpha x+4y=7\) and (9x+12y=21) have a unique solution?

Correct Answer: B. \(\alpha\neq3\). Explanation: अद्वितीय हल के लिए \(\frac{\alpha}{9}\neq\frac{4}{12}\) होना चाहिए। इसलिए \(\alpha\neq3\) सही शर्त है। / For a unique solution, \(\frac{\alpha}{9}\neq\frac{4}{12}\) must hold. Thus \(\alpha\neq3\) is correct.

Which concept should I revise for this Mathematics MCQ?

For a unique solution, \(\frac{\alpha}{9}\neq\frac{4}{12}\) must hold. Thus \(\alpha\neq3\) is correct.

What exam hint can help solve this Mathematics question?

अद्वितीय हल के लिए \(\frac{\alpha}{9}\neq\frac{4}{12}\) होना चाहिए। इसलिए \(\alpha\neq3\) सही शर्त है।

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