\(7x^2-22x+7=0\) के मूल क्या होंगे?
What will be the roots of \(7x^2-22x+7=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{11\pm6\sqrt{2}}{7}\)
Concept
Since (\left\(x-\frac{11}{7}\right\)2=\frac{72}{49}), \(x=\frac{11\pm6\sqrt{2}}{7}\). In exams, simplify \(\sqrt{72}=6\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(x=\frac{11\pm6\sqrt{2}}{7}\). Since (\left\(x-\frac{11}{7}\right\)2=\frac{72}{49}), \(x=\frac{11\pm6\sqrt{2}}{7}\). In exams, simplify \(\sqrt{72}=6\sqrt{2}\).
Exam Tip
(\left\(x-\frac{11}{7}\right\)2=\frac{72}{49}), इसलिए \(x=\frac{11\pm6\sqrt{2}}{7}\) है। परीक्षा में \(\sqrt{72}=6\sqrt{2}\) सरल करें।
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